NEET AIPMT Chemistry Chapter Wise Solutions – Solutions
NEET AIPMT Chemistry Chapter Wise SolutionsPhysicsBiology
1.If molality of the dilute solution is doubled, the value of molal depression constant (Kf) will be (NEET 2017)
(a) halved
(b) tripled
(c) unchanged
(d) doubled.
2.Which of the following is dependent on temperature? (NEET 2017)
(a) Molarity
(b) Mole fraction
(c) Weight percentage
(d) Molality
3.The van’t Hoff factor (i) for a dilute aqueous solution of the strong electrolyte barium hydroxide is (NEET-II 2016)
(a) 0
(b) 1
(c) 2
(d) 3
4.Which one of the following is incorrect for ideal solution?(NEET-II 2016)
(a)ΔHmix=0
(b)ΔUmix=0
(c)ΔP=Pobs-P=0
(d)ΔGmix=0
5. Which of the following statements about the composition of the vapour over an ideal 1 : 1 molar mixture of benzene and toluene is correct? Assume that the temperature is constant at 25°C. (Given, vapour pressure data at 25°C, benzene = 12.8 kPa, toluene = 3.85 kPa) (NEET-1 2016)
(a) The vapour will contain equal amounts of benzene and toluene.
(b) Not enough information is given to make a prediction.
(c) The vapour will contain a higher percentage of benzene.
(d) The vapour will contain a higher percentage of toluene.
6.At 100°C the vapour pressure of a solution of 6.5 g of a solute in 100 g water is 732 mm. If Kb = 0.52, the boiling point of this solution will be (NEET-1 2016)
(a) 102°C
(b) 103°C
(c) 101°C
(d) 100°C
7. What is the mole fraction of the solute in a 1.00 m aqueous solution? (2015, 2011)
(a) 1.770
(b) 0.0354
(c) 0.0177
(d) 0.177
8. The boiling point of 0.2 mol kg-1 solution of X in water is greater than equimolal solution of Y in water. Which one of the following statements is true in this case? (2015, Cancelled)
(a) Molecular mass of X is less than the molecular mass of Y.
(b) Y is undergoing dissociation in water while X undergoes no change.
(c) X is undergoing dissociation in water.
(d) Molecular mass of X is greater than the molecular mass of Y.
9. Which one of the fol lowing electrolytes has the same value of van’t Hoff factor (i) as that of Al2(S04)3 (if all are 100% ionised)?(2015, Cancelled)
(a) Al(N03)3
(b) K4Fe(CN)6]
(c) K2S04
(d) K3[Fe(CN)6]
10. Which of them is not equal to zero for an ideal solution? (2015, Cancelled)
(a) ΔVmix
(b) ΔP = Pobs-PRaoult
(c) ΔHmix
(d)ΔSmix
11. Of the following 0.10 m aqueous solutions, which one will exhibit the largest freezing point depression? (2014)
(a) KCl
(b) C6H1206
(c) Al2(S04)3
(d) K2SO4
12. How many grams of concentrated nitric acid solution should be used to prepare 250 mL of 2.0 M HN03? The concentrated acid is 70% HN03. (MEET 2013)
(a) 70.0 g cone. HN03
(b) 54.0 g cone. HN03
(c) 45.0 g cone. HN03
(d) 90.0 g cone. HN03
13. Which condition is not satisfied by an ideal ‘ solution? (Karnataka NEET 2013)
(a) ΔmixV=0
(b) ΔmixS=0
(c) Obeyance to Raoult’s Law
(d)ΔmixH=0
14. pA and pB are the vapour pressure of pure liquid components, A and B, respectively of an ideal binary solution. If xA represents the mole fraction of component A, the total pressure of the solution will be (2012)
(a) pA + xA(pB-pA)
(b) pA+xA(pA-pB)
(c) pB + xA(pB – pA)
(d) pB+xA(pA-pB)
15. Vapour pressure of chloroform (CHCl3) and dichloromethane (CH2Cl2) at 25°C are 200 mm Hg and 41.5 mm Hg respectively. Vapour pressure of the solution obtained by mixing 25.5 g of CHCl3 and 40 g of CH2Cl2 at the same temperature will be (Mains 2012)
(Molecular mass of CHCl3 = 119.5 u and molecular mass of CH2Cl2 = 85 u)
(a) 173.9 mm Hg
(b) 615.0 mm Hg
(c) 347.9 mm Hg
(d) 285.5 mm Hg
16. The freezing point depression constant for water is -1.86° C m-1. If 5.00 g Na2S04 is dissolved in 45.0 g H20, the freezing point is changed by -3.82°C. Calculate the van’t Hoff factor for Na2S04. (2011)
(a) 2.05
(b) 2.63
(c) 3.11
(d) 0.381
17. The van’t Hoff factor i for a compound which undergoes dissociation in one solvent and association in other solvent is respectively (2011)
(a) less than one and greater than one
(b) less than one and less than one
(c) greater than one and less than one
(d) greater than one and greater than one.
18. A 0.1 molal aqueous solution of a weak acid is 30% ionized. If Kf for water is 1.86°C/m, the freezing point of the solution will be (Mains 2011)
(a) -0.18°C
(b) -0.54°C
(c) – 0.36°C
(d) – 0.24°C
19. 200 mL of an aqueous solution of a protein contains its 1.26 g. The osmotic pressure of this solution at 300 K is found to be 2.57 x 10-3 bar. The molar mass of protein will be (R = 0.083 L bar mol-1K-1) (Mains 2011)
(a) 51022 g moL-1
(b) 122044 g moL-1
(c) 31011 g moL-1
(d) 61038 g moL-1
20. An aqueous solutionis 1.00 molal in KI. Which change will cause the vapour pressure of the solution to increase? (2010)
(a) Addition of NaCl
(b) Addition of Na2S04
(c) Addition of 1.00 piolal KI
(d) Addition of water
21. A solution of sucrose (molar mass = 342 g mol-1) has been prepared by dissolving 68.5 g of sucrose in 1000 g of water. The freezing point of the solution obtained will be (Kf for water = 1.86 K kg mol-1) : (2010)
(a) -0.372°C
(b) -0.520°C
(c) + 0.372°C
(d) -0.570“C
22. A 0.0020 m aqueous solution of an ionic compound [Co(NH3)5(No2)]Cl freezes at – 0.00732°C. Number of moles of ions which 1 mol of ionic compound produces on being dissolved in water will be (Kf=-1.86°C/m] (2009)
(a) 3
(b) 4
(c) 1
(d) 2
23. 0.5 molal aqueous solution of a weak acid (HX) is 20% ionized .If Kf for water is 1.86 K kg mol-1, the lowering in freezing point of the solution is (2007)
(a) 0.56 K
(b) 1.12 K
(c) -0.56 K
(d) 1.12 K
24. Concentrated aqueous sulphuric acid is 98% H2S04 by mass and has a density of 1.80 g mL-1 Volume of acid required to make one litre of 0.1 M H2S04 solution is (2007)
(a) 16.65 mL
(b) 22.20 mL
(c) 5.55 mL
(d) 11.10 mL
25. During osmosis, flow of water through a semipermeable membrane is (2006)
(a) from solution having lower concentration only
(b) from solution having higher concentration only
(c) from both sides of semipermeable membrane with equal flow rates
(d) from both sides of semipermeable membrane with unequal flow rates.
26. A solution of acetone in ethanol (2006)
(a) obeys Raoult’s law
(b) shows a negative deviation from Raoult’s law
(c) shows a positive deviation from Raoult’s law
(a) behaves like a near ideal solution.
27. 1.00 g of a non-electrolyte solute (molar mass 250 g mol-1) was dissolved in 51.2 g of benzene. If the freezing point depression constant, Kf of benzene is 5.12 K kg mol-1, the freezing point of benzene will be lowered by (2006)
(a) 0.2 K
(b) 0.4 K
(c) 0.3 K
(d) 0.5 K
28. A solution containing 10 g per dm³ of urea (molecular mass = 60 g mol-1) is isotonic with a 5% solution of a nonvolatile solute is (2006)
(a) 200 g mol-1
(b) 250 g mol-1
(c) 300 g mol-1
(d) 350 g mol-1
29. The mole fraction of the solute in one molal aqueous solution is (2005)
(a) 0.009
(b) 0.018
(c) 0.027
(d) 0.036
30. The vapour pressure of two liquids P and Q are 80 and 60 torr, respectively. The total vapour pressure of solution obtained by mixing 3 mole of P and 2 mol of Q would be (2005)
(a) 72 torr
(b) 140 torr
(c) 68 torr
(d) 20 torr
31. A solution has a 1 : 4 mole ratio of pentane to hexane. The vapour pressures of the pure hydrocarbons at 20°C are 440 mm Hg for pentane and 120 mm Hg for hexane. The mole fraction of pentane in the vapour phase would be (2005)
(a) 0.200
(b) 0.549
(c) 0.786
(d) 0.478
32. A solution of urea (mol. mass 56 g mol-1) boils at 100.18°C at the atmospheric pressure. If Kf and Kb for water are 1.86 and 0.512 K kg mol-1 respectively, the above solution will freeze at (2005)
(a) 0.654°C
(b) -0.654°C
(c) 6.54°C
(d) – 6.54°C
33. A solution containing components A and B follows Raoult’s law (2002)
(a) A – B attraction force is greater than A – A and B – B
(b) A – B attraction force is less than A – A and B-B
(c) A – B attraction force remains same as A – A and B-B
(d) volume of solution is different from sum of volume of solute and solvent.
34. A solution contains non volatile solute of molecular mass M2. Which of the following can be used to calculate the molecular mass of solute in terms of osmotic pressure? (2002)
(m2 = mass of solute, V = volume of solution, π = osmotic pressure)
35. 2.5 litre of 1 M NaOH solution is mixed with another 3 litre of 0.5 M NaOH solution. Then find out molarity of resultant solution. (2002)
(a) 0.80 M
(b) 1.0 M
(c) 0.73 M
(d) 0.50M
36. The beans are cooked earlier in pressure cooker because (2001)
(a) boiling point increases witlv increasing pressure
(b) boiling point decreases with increasing pressure
(c) extra pressure of pressure cooker softens the beans
(d) internal energy is not lost while cooking in pressure cooker.
37. Pure water can be obtained from sea water by (2001)
(a) centrifugation
(b) plasmolysis
(c) reverse osmosis
(d) sedimentation.
38. From the colligative properties of solution, which one is the best method for the determination of molecular weight of proteins and polymers? (2000)
(a) Osmotic pressure
(b) Lowering in vapour pressure
(c) Lowering in freezing point
(d) Elevation in boiling point
39. The vapour pressure of benzene at a certain temperature is 640 mm of Hg. A non-volatile and non-electrolyte solid, weighing 2.175 g is added to 39.08 of benzene. The vapour pressure of the solution is 600 mm of Hg. What is the molecular weight of solid substance? (1999)
(a) 69.5
(b) 59.6
(c) 49.50
(d) 79.8
40. How many g of dibasic acid (mol. weight 200) should be present in 100 mL of the aqueous solution to give strength of 0.1 N? (1999)
(a) 10 g
(b) 2 g
(c) 1 g
(d) 20 g
41. If 0.15 g of a solute, dissolved in 15 g of solvent, is boiled at a temperature higher by 0.216°C, than that of the pure solvent. The molecular weight of the substance (Molal elevation constant for the solvent is 2.16°C) is (1999)
(a) 10.1
(b) 100
(c) 1.01
(d) 1000
42. The vapour pressure of a solvent decreased by 10 mm of mercury when a non-volatile solute was added to the solvent. The mole fraction of the solute in the solution is 0.2. What should be the mole fraction of the solvent if the decrease in the vapour pressure is to be 20 mm of mercury? (1998)
(a) 0.4
(b) 0.6
(c) 0.8
(d) 0.2
43. A 5% solution of cane sugar (mol. wt. = 342) is isotonic with 1% solution of a substance X. The molecular weight of X is (1998)
(a) 68.4
(b) 171.2
(c) 34.2
(d) 136.8
44. Which of the following 0.10 m aqueous solution will have the lowest freezing point? (1997)
(a) KI
(b) C12H22011
(c) Al2(S04)3
(d) C5H10O5
45. What is the molarity of H2S04 solution, that has a density 1.84 g/cc at 35°C and contains 98% by weight? (1996)
(a) 18.4 M
(b) 18 M
c) 4.18 M
(d) 8.14M
46. The vapour pressure of CCL4 at 25°C is 143 mm Hg. If 0.5 g of a non-volatile solute (mol. weight = 65) is dissolved in 100 mL CCl4, the vapour pressure of the solution will be (1996)
(a) 199.34 mm Hg
(b) 143.99 mm Hg
(c) 141.43 mm Hg
(d) 94.39 mm Hg.
47. The relationship between osmotic pressure at 273 K when 10 g glucose (P1), 10 g urea (P2), and 10 g sucrose (P3) are dissolved in 250 mL of water is (1996)
(a) p2 > p1 > p3
(b) p2> p3> p1
(c) p1> p2> p3
(d) p3 > p1> p2
48. The concentration unit, independent of temperature, would be (1995, 1992)
(a) normality
(b) weight volume percent
(c) molality
(d) molarity.
49. According to Raoult’s law, the relative lowering of vapour pressure for a solution is equal to (1995)
(a) mole fraction of solute
(b) mole fraction of solvent
(c) moles of solute
(d) moles of solvent.
50. How many grams of CH3OH should be added to water to prepare 150 mL solution of 2 M CH3OH? (1994)
(a) 9.6 x 10³
(b) 2.4 x 10³
(c) 9.6
(d) 2.4
51. At 25°C, the highest osmotic pressure is exhibited by 0.1 M solution of (1994)
(a) glucose
(b) urea
(c) CaCl2
(d) KCl
52. Which of the following salt has the same value of vant’s Hoff factor (i) as that of K3[Fe(CN)6]? (1994)
(a) Na2S04
(b) Al(N03)3
(c) Al2(S04)3
(d) NaCl
53. If 0.1 M solution of glucose and 0.1 M solution of urea are placed on two sides of the semipermeable membrane to equal heights, then it will be correct to say that (1992)
(a) there will be no net movement across the membrane
(b) glucose will flow towards glucose solution
(c) urea will flow towards glucose solution
(d) water will flow from urea solution to glucose.
54. Which one is a colligative property? (1992)
(a) Boiling point
(b) Vapour pressure
(c) Osmotic pressure
(d) Freezing point
55. Blood cells retain their normal shape in solution which are (1991)
(a) hypotonic to blood
(b) isotonic to blood
(c) hypertonic to blood
(d) equinormal to blood.
56. Which of the following aqueous solution has minimum freezing point? (1991)
(a) 0.0 l m NaCl
(b) 0.005 m C2H5OH
(c) 0.005 m MgI2
(d) 0.005 m MgS04
57. The relative lowering of the vapour pressure is equal to the ratio between the number of (1991)
(a) solute molecules to the solvent molecules
(b) solute molecules to the total molecules in the solution
(c) solvent molecules to the total molecules in the solution
(d) solvent molecules to the total number of ions of the solute.
58. All form ideal solution except (1988)
(a) C6H6 and C6H5CH3
(b) C2H6 and C2H5I
(c) C6H5CI and C6H5Br
(d) C2H5I and C2H5OH
59. An ideal solution is formed when its components (1988)
(a) have no volume change on mixing
(b) have no enthalpy change on mixing
(c) have both the above characteristics
(d) have high solubility.
Answer Key
Explanations